Mathématiques

Question

factoriser: x² - x - 2

 

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1 Réponse

  • x²-x-2 = 0

    Δ = b²-4ac
    Δ = (-1)²-4*1*(-2)
    Δ = 1+8
    Δ = 9

    Δ > 0

    x
    ₁ = (-b-√Δ)/2a = [-(-1)-√9]/2*1 = (1-3)/2 = -2/2 = -1
    x₂ = (-b+√Δ)/2a = (1+3)/2 = 4/2 = 2

    factorisation pour Δ > 0 : a*(x-x₁)(x-x₂)

    x²-x-2 = 1*(x+1)(x-2)
    x²-x-2 = (x+1)(x-2)

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